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5n^2+7n-90=0
a = 5; b = 7; c = -90;
Δ = b2-4ac
Δ = 72-4·5·(-90)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-43}{2*5}=\frac{-50}{10} =-5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+43}{2*5}=\frac{36}{10} =3+3/5 $
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